PT

Benzene–toluene phase diagram and lever rule

H. K. D. H. Bhadeshia & H. Yan

Vapour–liquid equilibrium at isothermal T = 80 °C

Interactive P–z engine
Isothermal phase envelope (P–x,y)
Liquidus (bubble line) Vapourus (dew line)
Coordinates: z = 0.500, P = 0.600 atm
Presets:

The mechanical lever analogy

Fulcrum balances at overall composition z
Liquid arm (right segment) Length = (y − z). Governs the liquid fraction fL.
Vapour arm (left segment) Length = (z − x). Governs the vapour fraction fV.

State coordinates

System T = 80 °C
0.00 (Pure Toluene) 0.50 1.00 (Pure Benzene)
atm
0.200 atm 0.600 atm 1.000 atm
P*Toluene = 0.380 atm
P*Benzene = 1.000 atm

Thermodynamic state

Evaluating...
Bubble-point pressure Pbub(z)
0.690 atm
Dew-point pressure Pdew(z)
0.550 atm
Liquid fraction (fL) Vapour fraction (fV)
50.0% (0.500) 50.0% (0.500)

Theoretical foundation and derivation of the lever rule

Phase equilibrium in the binary Benzene (A) – Toluene (B) system

1. Raoult's law and boundaries

Benzene (A, normal b.p. 80.1 °C) and Toluene (B, normal b.p. 110.6 °C) form an ideal solution. At isothermal T = 80 °C:

  • P*A = 1.000 atm (pure Benzene)
  • P*B = 0.380 atm (pure Toluene)

Bubble-point line (liquidus): The equilibrium vapour pressure of liquid composition xA: P = xA P*A + (1 − xA) P*B This boundary is straight because partial vapour pressures are additive following Raoult's law.

Dew-point line (vapourus): Condensation pressure of vapour yA: P = 1 / [ yA / P*A + (1 − yA) / P*B ]

2. The horizontal tie-line

Within the two-phase envelope, the mixture splits into coexisting liquid and vapour at identical system pressure and temperature:

  • Point L on the liquidus: gives the liquid phase composition xA.
  • Point V on the vapourus: gives the vapour phase composition yA.
  • State point (z, P): sits directly on this horizontal tie line.

Because Benzene is more volatile than Toluene, the vapour phase is always enriched in Benzene compared to the equilibrium liquid (yA > xA).

3. Mathematical lever rule

Conserving total moles n = nL + nV with molar fractions fL = nL/n and fV = nV/n: z = fL xA + fV yA Substituting fL = 1 − fV yields: fV = (z − xA) / (yA − xA) and for the liquid phase: fL = (yA − z) / (yA − xA)

The inverse rule: The liquid fraction is proportional to the distance from the state point to the vapour boundary (yA − z), and vice versa.