H.K.D.H. Bhadeshia,
Phase Transformations Group,
Department of Materials Science and Metallurgy,
University of Cambridge,
Cambridge, U.K.
Calculates the heat output of a welding arc.
Language: | FORTRAN |
Product form: | Source code |
MAP_STEEL_RWELD calculates the heat output using the formula:
HEAT = VOLT*CURR/SPEED
with no account being taken of the arc weld efficiency.
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No information supplied.
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DOUBLE PRECISION CURR, VOLT, SPEED, HEAT WRITE (*,*) 'Input current, voltage and speed:' READ (*,*) CURR, VOLT, SPEED CALL MAP_STEEL_RWELD(CURR, VOLT, SPEED, HEAT) WRITE (*,1) CURR, VOLT, SPEED WRITE (*,2) HEAT STOP 1 FORMAT(1H /'Current= ',F10.2,' Amps.'/'Voltage= ',F10.2,' Volts'/ & 'Speed= ',F10.5,' m/s') 2 FORMAT('The heat output is ',D11.4,' J/m') END
Input current, voltage and speed: 400 30 0.01
Current= 400.00 Amps. Voltage= 30.00 Volts Speed= 0.01000 m/s The heat output is 0.1200D+07 J/m
None.
heat, efficiency, weld
MAP originated from a joint project of the National Physical Laboratory and the University of Cambridge.
MAP Website administration / map@msm.cam.ac.uk