H.K.D.H. Bhadeshia,
Phase Transformations Group,
Department of Materials Science and Metallurgy,
University of Cambridge,
Cambridge, U.K.
Calculates the heat output of a welding arc.
| Language: | FORTRAN |
| Product form: | Source code |
MAP_STEEL_RWELD calculates the heat output using the formula:
HEAT = VOLT*CURR/SPEED
with no account being taken of the arc weld efficiency.
None supplied.
None.
No information supplied.
None.
DOUBLE PRECISION CURR, VOLT, SPEED, HEAT
WRITE (*,*) 'Input current, voltage and speed:'
READ (*,*) CURR, VOLT, SPEED
CALL MAP_STEEL_RWELD(CURR, VOLT, SPEED, HEAT)
WRITE (*,1) CURR, VOLT, SPEED
WRITE (*,2) HEAT
STOP
1 FORMAT(1H /'Current= ',F10.2,' Amps.'/'Voltage= ',F10.2,' Volts'/
& 'Speed= ',F10.5,' m/s')
2 FORMAT('The heat output is ',D11.4,' J/m')
END
Input current, voltage and speed: 400 30 0.01
Current= 400.00 Amps. Voltage= 30.00 Volts Speed= 0.01000 m/s The heat output is 0.1200D+07 J/m
None.
heat, efficiency, weld
MAP originated from a joint project of the National Physical Laboratory and the University of Cambridge.
MAP Website administration / map@msm.cam.ac.uk